Given 2 strings, find the longest common subsequence using dynamic programming.
public class LongCommonSubSequence {
//Returns length of LCS for x[0..m-1], y[0..n-1]
public static int lcs(String x, String y) {
int M = x.length();
int N = y.length();
// opt[i][j] = length of LCS of x[i..M] and y[j..N]
int[][] opt = new int[M + 1][N + 1];
// compute length of LCS and all subproblems via dynamic programming
for (int i = M - 1; i >= 0; i--) {
for (int j = N - 1; j >= 0; j--) {
if (x.charAt(i) == y.charAt(j))
opt[i][j] = opt[i + 1][j + 1] + 1;
else
opt[i][j] = Math.max(opt[i + 1][j], opt[i][j + 1]);
}
}
// recover LCS itself and print it to standard output
int i = 0, j = 0;
while (i < M && j < N) {
if (x.charAt(i) == y.charAt(j)) {
System.out.print(x.charAt(i));
i++;
j++;
} else if (opt[i + 1][j] >= opt[i][j + 1])
i++;
else
j++;
}
System.out.println();
return opt[0][0];
}
/* Driver program to test above function */
public static void main(String args[]) {
String str1 = "AGGTAB";
String str2 = "GXTXAYB";
System.out.println("Length of LCS is" + lcs(str1, str2));
}
}
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